What is the magnitude of the electric field 17.1 cm directly above an isolated 1.83ã10â5 c charge?

Electric field,

Explanation:

Given that,

Charge,

We need to find the magnitude of electric field 17.1 cm (0.171 m) above an isolated charge. Electric field at a point is given by :

So, the electric field is . Hence, this is the required solution.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

the answer is 3.1 his answer is wrong mines is right