Acapacitor has a charge of 4.6 î¼c. an e-field of 1.8 kv/mm is desired between the plates. there's no dielectric. what must be the area of each plate?

Explanation:

As we know that

E = 1.8 kV/mm

now we know that electric field between the plated of capacitor is given as

now we will have

now we have

now we have area of the plates of capacitor

i wanna say it’s between b and d, leaning more towards b.

c)as speed changes, wavelength and frequency change.

everything changes!