Aparallel-plate air capacitor with a capacitance of 260 pf has a charge of magnitude 0.155 î¼c on each plate. the plates have a separation of 0.313 mm. what is the potential difference between the plates?

The potential difference between the plates is 596.2 volts.

Explanation:

Given that,

Capacitance

Charge

Separation of plates = 0.313 mm

We need to calculate the potential difference between the plates

Using formula of potential difference

Where, Q = charge

C = capacitance

Put the value into the formula

Hence,The potential difference between the plates is 596.2 volts.

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5