Does the initial velocity of an object have anything to do with its acceleration? for example, compared to dropping an object, if you throw it downward would the acceleration be different after you released it?

Explanation:

This is an excellent question to get an answer for. It teaches you much about the nature of physics.

The answer is no.

The distance will be quite different. The time might be different in getting to the distance.  But the acceleration will be the same in either case.

How do you know? Look at one of the formulas, say

d = vi * t + 1/2*a * t^2

What does vi do? vi will alter both t and d. if vi = 0 then both d and/or t will be found. But what will "a" do? Is there anything else acting in the up or down line of action? You should answer no.

If vi is not zero, t will be less and d will take less time to get where it is going.

divide the right side by the left side

0.024÷1.2=0.02 for example

i will answer your question if you answer mine