Along jumper can jump a distance of 7.4 m when he takes off at an angle of 45° with respect to the horizontal. assuming he can jump with the same initial speed at all angles, how much distance does he lose (in m) by taking off at 429?

0.02 m

Explanation:

R₁ = initial distance jumped by jumper = 7.4 m

R₂ = final distance jumped by jumper = ?

θ₁ = initial angle of jump = 45°

θ₂ = final angle of jump = 42.9°

= speed at which jumper jumps at all time

initial distance jumped is given as

final distance jumped is given as

Dividing final distance by initial distance

distance lost is given as

d =

d = 7.4 - 7.38

d = 0.02 m

prolly a beacuse the momentuem the car has increases while going down hill

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2