Auniform steel plate has an area of 0.897 m^2. when subjected to a temperature difference between its sides, a heat current of 27700 w is found to flow h it. what is the temperature gradient? what is the temperature difference when the plate is 0.0537 m thick? the thermal conductivity of steel is 50.2 w/(m k).

The answer is a) taiga because taigas are cold

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.