A0.8 g object is placed in a 534 n/c uniform electric field. upon being released from rest, it moves 12 m in 1.2 s. determine the object's acceleration & charge magnitude. assume the acceleration is due to the e-field (i. e., ignore all other forces).

Explanation:

It is given that,

Mass of the object, m = 0.8 g = 0.0008 kg

Electric field, E = 534 N/C

Distance, s = 12 m

Time, t = 1.2 s

We need to find the acceleration of the object. It can be solved as :

m a = q E.......(1)

m = mass of electron

a = acceleration

q = charge on electron

"a" can be calculated using second equation of motion as :

a = 16.67 m/s²

Now put the value of a in equation (1) as :

q = 0.0000249 C

or

Hence, this is the required solution.