A65.0-ω resistor is connected to the terminals of a battery whose emf is 12.0 v and whose internal resistance is 0.5 ω. calculate (a) the current in the circuit, (b) the terminal voltage of the battery, vab, and (c) the power dissipated in the resistor r and in the battery’s internal resistance r.

a) 0.1832 A

b) 11.91 Volts

c) 2.18 Watt , 0.0168 Watt

Explanation:

(a)

R = external resistor connected to the terminals of the battery = 65 Ω

E = Emf of the battery = 12.0 Volts

r = internal resistance of the battery = 0.5 Ω

i = current flowing in the circuit

Using ohm's law

E = i (R + r)

12 = i (65 + 0.5)

i = 0.1832 A

(b)

Terminal voltage is given as

= i R

= (0.1832) (65)

= 11.91 Volts

(c)

Power dissipated in the resister R is given as

= i²R

= (0.1832)²(65)

= 2.18 Watt

Power dissipated in the internal resistance is given as

= i²r

= (0.1832)²(0.5)

= 0.0168 Watt

sleep paralysis is a parasomnia, events associated with sleep.

sleep paralysis happens when you are in the middle of waking up or falling asleep. it is the feeling of being conscious but unable to move. it definitely involves hallucinations.

i had a friend that had sleep paralysis and he told me a story one time where he was laying in bed and he couldn't move his body no matter how hard he tried and there was someone standing in the corner of his room coming towards him. he couldn't move and you can't "wake up" because you are already conscious. sometimes sleep paralysis can be triggered by frequent waking up during the night based off of multiple trips to the bathroom, or if you had ever been abused, sleep paralysis can start happening from things like that.

i think its c if i'm wrong