Asoftball player hits a ball at
29.5 m/s at a 33.0° angle. an
outfielder catches the ball at the same height. how far was the
outfielder from the hitter?

81.1 m

Explanation:

Given:

x₀ = 0 m

y₀ = y = 0 m

v₀ₓ = 29.5 cos 33.0° m/s

v₀ᵧ = 29.5 sin 33.0° m/s

aₓ = 0 m/s²

aᵧ = -9.8 m/s²

Find:

x

First, find the time it takes to land.

y = y₀ + v₀ᵧ t + ½ aᵧt²

0 = 0 + (29.5 sin 33.0) t - 4.9 t²

t = (29.5 sin 33.0) / 4.9

t = 3.28 s

Now in the x direction:

x = x₀ + v₀ₓ t + ½ aₓt²

x = 0 + (29.5 cos 33.0) (3.28) + 0

x = 81.1 m

The outfielder was 81.1 meters away.

answer: 0.20

explanation: this can only be the answew because all the other measuremnets are not close

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.