The velocity field of a steady flow is given as v=(u0+bx)i? b y j , where u0 and b are constant. find the acceleration in the x- and y-directions if u0=1m/ s and b=0.3m .

Explanation:

The velocity field o a steady flow is given by :

Where

U₀ and b are constant

We know that, the acceleration is given by :

a = b i

a = 0.3 m/s²

So, acceleration corresponding to this velocity is 0.3 m/s². Hence, this is the required solution.

c.the charges if the proton and electron and gravity

0.11 m/s and 0.28 m/s should be correct