Consider a car that is initially traveling along a straight stretch of highway at 15 m/s. at t=0 the car begins to accelerate at 2.0 m/s2 in order to pass a truck. the final velocity is vx=25m/s. calculate how far the car travels during its 5.0 s of acceleration.

The car travels 100 meter during its 5.0 s of acceleration

Explanation:

We have the equation of motion v²=u²+2as, where v is the final velocity, u is the initial velocity, a is the acceleration ans s is the displacement.

v = 25 m/s

a = 2 m/s²

u = 15 m/s

Substituting

      25²=15²+2 x 2 x s

       s = 100 m

The car travels 100 meter during its 5.0 s of acceleration

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

i think the answer would be b