Suppose div f = xyz2. (a) find div f at the point (1, 3, 1). (note: you are given div f, not f.) div f (1, 3, 1) = (b) using your answer to part (a), but no other information about the vector field f, estimate the flux out of a small box of side 0.2 centered at the point (1, 3, 1) and with edges parallel to the axes. (c) without computing the vector field f, calculate the exact flux out of the box. (round your answer to five decimal places.)

Alinear relationship would look like a straight line on the graph. it could have a positive negative or 0 slope. so it could be a line potentially going in any direction but it must be perfectly straight.

Answer choices? if there is any

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j