Arod 10.0 cm long is uniformly charged and has a total charge of -21.0 µc. determine the magnitude and direction of the electric field along the axis of the rod at a point 34.0 cm from its center.

The magnitude of electric field is and the direction is inward.

Explanation:

Given that,

Length of rod = 10.0 cm

Charge

Distance D = (34.0-10) cm = 0.24 m

We need to calculate the electric field along the axis

Where, Q = charge

D = distance

Put the value into the formula

Negative sign shows the direction of electric field is inward that means toward the center.

Hence, The magnitude of electric field is and the direction is inward.

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