An electron travels undeflected in a path that is perpendicular to an electric feld of 8.3 x 10 v/m. it is also moving perpendicular to a magnetic field with a magnitude of 7.3 x 103 t. if the electric field is turned off, at what radius would the electron orbit? o 124 x 10*m 889 x 104 m o 9.85 x 104m o 1.06 x 10o m

Explanation:

Initially, the electron is travelling undeflected at constant speed- this means that the electric force and the magnetic force acting on the electron are balanced. So we can write

q E = q v B

where

q is the electron's charge

is the electric field magnitude

v is the electron's speed

is the magnitude of the magnetic field

Solving for v,

Then the electric field is turned off, so the electron (under the influence of the magnetic field only) will start moving in a circle of radius r. Therefore, the magnetic force will be equal to the centripetal force:

where

is the electron's charge

is the electron's mass

Solving for r, we find the radius of the electron's orbit:

the pull of gravity on the rocket decreases

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