Which describes an object in projectile motion? check all that apply. gravity acts to pull the object down. the object moves in a straight path. the forward velocity of the object is 0 m/s. the object’s inertia carries it forward. the path of the object is curved. the object moves both forward and up.

Gravity acts to pull the object down.

The object’s inertia carries it forward.

The path of the object is curved.

Explanation:

The motion of a projectile consists of two independent motion:

- A uniform motion along the x (horizontal) direction, with constant velocity equal to the horizontal component of the initial velocity of the object

- An accelerated motion along the y (vertical) direction, with constant acceleration equal to the acceleration of gravity (g = 9.8 m/s^2, downward), so with a vertical velocity increasing. This acceleration is due to the presence of the force of gravity, that pulls the object down.

So the following statements are true:

Gravity acts to pull the object down.

The object’s inertia carries it forward. --> in fact, there are no forces along the horizontal direction, so the object continues its uniform motion due to inertia

The path of the object is curved. --> in fact, the composition of the two motions (uniform along the x-axis and accelerated along the y-axis) gives a curved trajectory (specifically, a parabolic trajectory).

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

gravity

explanation: