Aa a of 22 m/s at an of 36.9 .be . a. b. c. (3)x y of? (3)go? (4) () it to to ?

Answers:

a. Vx=17.6m/s
Vy=13.2m/s

b. 8.90m

c. 1.80s

Vi=22m/s

Theta=36.9deg

Vx=Vi*cos(theta)

Vy=Vi*sin(theta)

h(Max)=Vi^2*sin(theta)^2/2g

t(max height)= Vy/g

Vx=22*cos(36.9)=17.6m/s

Vy=22*sin(36.9)=13.2m/s

h(Max)=22^2*sin(36.9)^2/2(9.8)=8.90m

t(Max height)=17.6/9.8=1.80s

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