Alunar lander is making its descent to the moon base i. the lander descends slowly under the reto-thrust of its descent engine. the engine is cut off when the lander is 5.0m above the surface and has a downward speed of 1.5m/s. with the engine off, the lander is in free fall. what is the speed of the lander just before it touches the surface? the acceleration due to gravity on the moon is 1.6m/s^2

-4m/s

Explanation:

This problem is a good example of Free Fall, where the main condition is that the initial velocity must be zero , and the main equations for this situation as follows:

 (1)

  (2)

Where:

is the final height of the lunar lander

 is the initial height of the lunar lander (we are told the engine is cut off when the lander is 5.0m above the surface)

is the initial velocity of the lunar lander (we are told when the engine is off at 5m, the lander is in free fall)

is the time

is the acceleration due to gravity on the moon

Having this clear, let's start finding from (1):

 (3)

 (4)

 (5)

Substituting (5) in (2):

  (6)

Finally:

 Note the velocity is negative because of the downward trajectory of the lunar lander due to the free fall.

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .

a lot of it means it can be "burned" for energy and sold at one price. if it is scarce, the price will go up