Ahot-air balloonist, rising vertically with a constant speed of 5.00 m/s releases a sandbag at the instant the balloon is 40.0 m above the ground. after it is released, the sandbag encounters no appreciable air drag. compute the velocity of the sandbag at 0.250 s after its release.

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Explanation:

Take the direction up (where the hot-air balloonist moves) as the positive direction, and take the direction down (contrary to the direction of the hot-air balloonist) as the negative direction.

Then we propose the kinematic equation for the speed of the sandbag:

.

Where

is the initial velocity of the sandbag

a is the acceleration of the sandbag

t is the time in seconds.

In this case

a is the gravitational acceleration of

Now we substitute these values into the formula and solve for

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