A90db sound wave strikes an eardrum whose area is 5.0×10^-5m^2. how much energy is absorbed by the eardrum per second

-- The reference level for sound wave intensity is the threshold of human hearing, defined as  10⁻¹² W/m² .

-- This question is talking about a 90dB sound.  So its intensity is 10⁻³ W/m² .

-- The question tells us the size of the area that this sound is hitting.  So the power absorbed by that area is ...

Power = (intensity) x (area)

Power = (10⁻³ W/m²) x (5 x 10⁻⁵ m²)

Power = (10⁻³ x 5 x 10⁻⁵) W

Power = 5 x 10⁻⁸ Watts

(That's 5 x 10⁻⁸ Joules of energy per second.)

a, c, d, e are all applying about success strategies.

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.