During takeoff, an airplane climbs with a speed of 150 m/s at an angle of 45 degrees above the horizontal. the speed and direction of the airplane constitute a vector quantity known as the velocity. the sun is shining directly overhead. how fast is the shadow of the plane moving along the ground

106.1 m/s

Explanation:

The shadow of the plane is moving at the same velocity as the horizontal component of the airplane's velocity.

The horizontal component of the airplane's velocity is

where

v = 150 m/s is the velocity of the airplane

is the angle between the airplane's velocity and the horizontal

Substituting,

So, the shadow is moving at 106.1 m/s as well.

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this