Physics, 24.06.2019 03:50 jwbri

Consider an electric field perpendicular to a work bench. when a small charged sphere of mass 3.62 g and charge −19.9 µc is carefully placed in the field, the sphere is in static equilibrium. what are the magnitude and direction of the electric field? (give the magnitude in n/c.)

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The magnitude of the electric field is 1782.7 N/C. The direction of the electric field is in the downward direction due to the negative charge on the charged sphere.

What is the magnitude of an electric field?

The magnitude of an electric field refers to the force in each electric charge on the test charge.

From the parameters given:

The static equilibrium indicates that the electric field is in a balanced position.

Thus, the magnitude of the electric field can be computed by using the formula:

$\mathbf{E =\dfrac{F}{q}}$

$\mathbf{E =\dfrac{m \times g}{q}}$

$\mathbf{E =\dfrac{0.00362 \ kg \times 9.8 \ m/s^2}{19.9\times 10^{-6} C}}$

E = 1782.71 N/C

However, the direction of the electric field is in the downward direction due to the negative charge on the charged sphere.

Learn more about the electric field here:

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Answer from: Softball5378

1782.7 N/C, downward

Explanation:

Since the charged sphere is in static equilibrium, it means that the electric force acting is balanced with the weight of the sphere, so we can write:

$F_G = F_E\\mg = qE$

where

m = 3.62 g = 0.00362 kg is the mass of the sphere

g = 9.8 m/s^2 is the acceleration of gravity

$q=19.9 \mu C= 19.9\cdot 10^{-6}C$ is the magnitude of the charge

E is the magnitude of the electric field

Solving for E,

$E=\frac{mg}{q}=\frac{(0.00362 kg)(9.8 m/s^2)}{19.9\cdot 10^{-6} C}=1782.7 N/C$

In order for the sphere to be in equilibrium, the electric force must be in opposite direction to the weight, so the electric force must point upward. Since the sphere has a negative charge, the electric field has opposite direction to the electric force: so, the electric field direction is downward.

Answer from: Quest

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic = - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

Answer from: Quest

Rain is pulled by gravity which is a non contact force

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Consider an electric field perpendicular to a work bench. when a small charged sphere of mass 3.62 g...

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