Need asap ! a television of mass 15 kg sits on a table the coefficient of static friction between the table and the television is 0.35 what is the minimum applied force that will cause the television to slide? a. 79 nb. 38 nc. 147 nd. 51 n

D. 51 N. The minimum applied force that will cause the television slide is 51 N.

In order to solve this problem we have to use the force of static friction equation Fs = μs*n, where μs is the coefficient of static friction, and n is the normal force m*g.

With μs = 0.35, and n = 15kg*9.8m/s² = 147 N

Fs = (0.35)(147 N)

Fs = 51.45 N

Fs ≅ 51 N

answer: good job it's all correct !

explanation: