Asecond order low pass filter is generally characterized by the following transfer function: �(��) = �' ( (� �)( + � + �' � - + �' ( = 1 (� �)( �' ( + � + 1 ��' - + 1 analyze the relation between the input and output voltage for the circuit in figure 2a (sallen-key second order low-pass filter), and prove that the transfer function, resonant frequency and the quality factor are given by �(��) = 1 1 + ���((�1 + �() − �(�1�(�1�( �' = 1 2�6�1�(�1�( � = 6�1�(�1�( �((�1 + �() design a low pass active filter with 1 khz resonant frequency and a q = 1. because there are multiple parameters for this design, it is good practice to fix the resistor values, and set the capacitors to be integer multiples of one another. for example, let �1 = �( = � and c2 = n c1 where n is an integer, and solve for the value of n that satisfies the q-value. let c1 = 50uf and choose the value of r that satisfy the resonant frequency f0. for the designed filter, draw the absolute of the transfer function |h(ω)| verses frequency.

some think that theories become laws, but theories and laws have separate and distinct roles in the scientific method. a law is a description of an observed phenomenon in the natural world that hold true every time it is tested. it doesn't explain why something is true; it just states that it is true.

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momentum of soft ball three times less than baskey ball

the following is queen elizabeth’s purposes:

- to encourage the parliament that the technique of picking successors to the seat based merely on birthright needs to be reviewed.

- (not) to convince the parliament that her kid should not be measured as a likely choice for heir to the english power.

- to persuade the parliament that merely since she has a child does not assure that the kid will be a capable leader.

- to sway the parliament how shattering it could be if they proceeded discourteously concerning her or her child.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft