Amodel airplane with a mass of 0.741kg is tethered by a wire so that it flies in a circle 30.9 m in radius. the airplane engine provides anet thrust of 0.795 n perpendicular tothe tethering wire. (a) find the torque the net thrust producesabout the center of the circle. n·m (b) find the angular acceleration of the airplane when it is inlevel flight. rad/s2 (c) find the linear acceleration of the airplane tangent to itsflight path. m/s2

(a) 24.6 Nm

The torque produced by the net thrust about the center of the circle is given by:

where

F is the magnitude of the thrust

r is the radius of the wire

Here we have

F = 0.795 N

r = 30.9 m

Therefore, the torque produced is

(b)

The equivalent of Newton's second law for a rotational motion is

where

is the torque

I is the moment of inertia

is the angular acceleration

If we consider the airplane as a point mass with mass m = 0.741 kg, then its moment of inertia is

And so we can solve the previous equation to find the angular acceleration:

(c)

The linear acceleration (tangential acceleration) in a rotational motion is given by

where in this problem we have

is the angular acceleration

r = 30.9 m is the radius

Substituting the values, we find

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop