Physics, 25.06.2019 12:00 shukriabdisabrie
A6.34 kg particle with velocity v (vector) = (5.46 m/s)^ i ( 1.59 m/s)^ j is at x = 9.64 m, y = 5.84 m. it is pulled by a 9.92 n force in the negative x direction. about the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing?
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A6.34 kg particle with velocity v (vector) = (5.46 m/s)^ i ( 1.59 m/s)^ j is at x = 9.64 m, y = 5.84...
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