In 1913 niels bohr formulated a method of calculating the different energy levels of the hydrogen atom. he did this by combining both classical and quantum ideas. in this problem, we go through the steps needed to understand the bohr model of the atom. consider an electron with charge -e and mass m orbiting in a circle around a hydrogen nucleus(a single proton) with charge +e . in the classical model, the electron orbits around the nucleus, being held in orbit by the electromagnetic interaction between itself and the protons in the nucleus, much like planets orbit around the sun, being held in orbit by their gravitational interaction. when the electron is in a circular orbit, it must meet the condition for circular motion: the magnitude of the net force toward the center, fc, is equal to mv2 / r. given these two pieces of information, deduce the velocity v of the electron as it orbits around the nucleus. express your answer in terms of e, m, r, and epsilon 0, the permittivity of free space.

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

                                              ⇒      

here   k is the proportionality constant whose value is 1.

                                                            [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j