Acharge of 8.4 × 10–4 c moves at an angle of 35° to a magnetic field that has a field strength of 6.7 × 10–3 t. if the magnetic force is 3.5 × 10–2 n, how fast is the charge

10842.33m/s

Explanation:

F=qvBsine

V=f/(qBsine)

V=(3.5×10^-2)÷(8.4×10^-4×6.7×10^-3×sin35)

V=10842.33m/s

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.