A)find the minimum magnetic field needed to exert a 5.7 fn force on an electron moving at 23mm/s .b)find the field strength required if the field were at 45 degrees to the electron's velocity.

The minimum magnetic field needed to exert the given force is

When the field is 45 degrees to the electron's speed, the magnetic field strength is

The given parameters;

The minimum magnetic field is calculated as follows;

When the field is 45 degrees to the electron's speed, the magnetic field strength is calculated as follows;

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a)

The magnetic force exerted on a charged particle in motion is given by:

where

q is the charge of the particle

v is the velocity of the particle

B is the magnetic field strength

is the angle between the direction of v and B

The expression can be rewritten as

We see that the minimum magnetic field needed is the one for which , so with . In this problem, we have:

(charge of the electron)

is the force

is the electron's velocity

Substituting, we find

b)

In this case, the field is at 45 degrees to the electron's velocity, so we have

Therefore, the field strength required to obtain a force of

is the force

will be equal to

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!