A0.50-kg ball that is traveling at 6.0 m/s collides head-on with a 1.00-kg ball moving in the opposite direction at a speed of 12.0 m/s. the 0.50-kg ball bounces backward at 14 m/s after the collision. find the speed of the second ball after the collision.

-2 m/s

Explanation:

Assuming the collision is elastic, the total momentum must be conserved:

where

m1 = 0.50 kg is the mass of the first ball

m2 = 1.00 kg is the mass of the second ball

u1 = +6.0 m/s is the initial velocity of the first ball

u2 = -12.0 m/s is the initial velocity of the second ball

v1 = -14 m/s is the final velocity of the first ball

v2 = ? is the final velocity of the second ball

By re-arranging the equation, we can find the final velocity of the 1.00 kg ball:

which means, 2 m/s in the same direction the second ball was travelling before the collision.

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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