At the moment t = 0, a 20.0 v battery is connected to a 5.00 mh coil and a 6.00 ω resistor. (a) immediately thereafter, how does the potential difference across the resistor compare to the emf across the coil? (enter your answers in v.) resistor v coil v (b) answer the same question about the circuit several seconds later. (enter your answers in v.) resistor v coil v (c) is there an instant at which these two voltages are equal in magnitude? yes no (d) if so, when? is there more than one such instant? (enter all possible times in ms as a comma-separated list. if there are no such instants, enter none.) ms (e) after a 3.20 a current is established in the resistor and coil, the battery is suddenly replaced by a short circuit. answer questions (a) and (b) again with reference to this new circuit. (enter your answers in v.) immediately thereafter several seconds later resistor v v need ?

(a) On the coil: 20 V, on the resistor: 0 V

The sum of the potential difference across the coil and the potential difference across the resistor is equal to the voltage provided by the battery, V = 20 V:

The potential difference across the inductance is given by

(1)

where

is the time constant of the circuit

At time t=0,

So, all the potential difference is across the coil, therefore the potential difference across the resistor will be zero:

(b) On the coil: 0 V, on the resistor: 20 V

Here we are analyzing the situation several seconds later, which means that we are analyzing the situation for

Since is at the order of less than milliseconds.

Using eq.(1), we see that for , the exponential becomes zero, and therefore the potential difference across the coil is zero:

Therefore, the potential difference across the resistor will be

(c) Yes

The two voltages will be equal when:

(2)

Reminding also that the sum of the two voltages must be equal to the voltage of the battery:

And rewriting this equation,

Substituting into (2) we find

So, the two voltages will be equal when they are both equal to 10 V.

(d) at

We said that the two voltages will be equal when

Using eq.(1), and this last equation, this means

And solving the equation for t, we find the time t at which the two voltages are equal:

(e-a) -19.2 V on the coil, 19.2 V on the resistor

Here we have that the current in the circuit is

The problem says this current is stable: this means that we are in a situation in which , so the coil has no longer influence on the circuit, which is operating as it is a normal circuit with only one resistor. Therefore, we can find the potential difference across the resistor using Ohm's law

Then the battery is removed from the circuit: this means that the coil will discharge through the resistor.

The voltage on the coil is given by

(1)

which means that it is maximum at the moment when the battery is disconnected, when t=0:

And V this time is the voltage across the resistor, 19.2 V (because the coil is now connected to the resistor, not to the battery). So, the voltage across the coil will be -19.2 V, and the voltage across the resistor will be the same in magnitude, 19.2 V (since the coil and the resistor are connected to the same points in the circuit): however, the signs of the potential difference will be opposite.

(e-b) 0 V on both

After several seconds,

If we use this approximation into the formula

(1)

We find that

And since now the resistor is directly connected to the coil, the voltage in the resistor will be the same as the coil, so 0 V. This means that the coil has completely discharged, and current is no longer flowing through the circuit.

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .