If 0.45kg is changed by a reversible process to steam at 100°c, determine the entropy of: 1. the water 2. the surrounding. 3. the universe (water+surroundings) as a whole.

1) 2726.5 J/K      2) decrease                     3) 0

Explanation:

1)

change in entropy is given by

here Q=mL where L is the latent heat of vaporization. therefore

2)

since the heat is taken from surroundings, the change in entropy is negative therefore entropy of surrounding will decrease.

3) since there is no heat exchange with universe  therefore , Q=0 in this case

chemical properties of thing

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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