Auniform electric field e=15 n/c points downwards. a particle with charge q=-0.15 c is placed in the electric field. what is the magnitude and direction of the force on the particle?

2.25 N upwards

Explanation:

800 N/C to the right

Explanation:

The equation that relates force on a charge, electric field and charge is

where

F is the force acting on the charge

q is the charge

E is the electric field

In this problem, we have

is the electric field

is the charge

Substituting into the formula, we find the force

Concerning the direction:

- The electric field and the force have same directions if the charge is positive

- The electric field and the force have opposite directions if the charge is negative

Here the charge is negative, so the electric field has opposite direction to the force: therefore, it must be upwards.