Acar is rolling backward when it hits the gas. after 8.25 s it is moving forward at 8.62m/s, and is 12.9m to the right of its starting pount. what was its starting velocity ?

Explanation:

The given data is as follows.

        Final velocity (v) = 8.62 m/s,         Initial velocity () = ?

         time = 8.25 sec,          distance (s) = 12.9 m

Hence, formula to calculate the initial velocity is as follows.

                   v =

                 8.62 m/s =

                = 8.62 m/s - 8.25a ......... (1)

Also,   s = ...... (2)

Therefore, substitute the value of from equation (1) into equation (2) as follows.

                s =

               s = ....... (3)  

Now, putting the values of s and t into equation (3) as follows.

         s =  

        12.9 m =  

               a = 1.71  

Therefore, using equation (1) the value of initial velocity will be as follows.

                      =

                              =

                              = -5.49 m/s

Thus, we can conclude that starting velocity of the car is -5.49 m/s.

current flows in a wire

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day