100 points! a ball is thrown 19.0 m/s at an angle of 40.0º with the horizontal. assume the ball is thrown at ground level 22.0 meters away. a. how long does it take the ball to reach the wall? b. at what height does the ball hit the wall?

A. 1.51 seconds

B. 7.26 meters

Explanation:

A. Time to reach 22 meters

Find horizontal component of initial velocity V = 19 m/s:

Vx= Vcos(theta) = 19cos(40)  = 14.55 m/s

Use equation d= V0t + (1/2)at^2 to find the time

(acceleration is 0 for horizontal component) so: d = Vx*t

t = d/Vx = 22/14.55 = 1.51 seconds

B. Find vertical component of initial velocity:

Vy= Vsin(theta) = 19sin(40) = 12.21

Use equation y = V0*t + (1/2)at^2 to find the height at 1.51 seconds

y = (12.21)(1.51) + (.5)(-9.81)(1.51)^2

y= 7.26 meters

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

-reverse card

which piece of furniture will have the most inertia and give the furniture movers the most difficulty in moving?  

answer

a 75kg dining table