A225 kg bumper is moving north at .98 m/s when it hits a 198 kg car moving north at .28 m/s. the 198 kg car is moving north at .71 m/s after the collision. what is the post collision velocity of the 225 kg car?

= 60.16 cm/s or 0.6 m/s

Explanation:

Using the formula for collision;

M1U1 + M2U2 = M1V1 + M2V2

Therefore;

(225 kg)•(98 cm/s) + (198 kg)•(28 m/s) = (225 kg)•v + (198 kg)•(71 cm/s)

22050 kg•cm/s + 5544 kg•cm/s = (225 kg)•v + 14058 kg•cm/s

13536 kg•cm/s = (225 kg)•v

v = 60.16 cm/s

Therefore; the post collision velocity of the 225 kg car is 60.16 cm/s

-4 on

higher potential

explanation:

because it is in a high speed so it must move into a of high potential