The student places 0.5 kg of potato into a pan of water.
during cooking, the temperature of the potato increases from 20 °c to 100 °c
the specific heat capacity of the potato is 3400 j/kg °c
calculate the change in thermal energy of the potato.
use the equation:
change in thermal energy = mass * specific heat capacity temperature change
[3 marks]

136000 J or 136 kJ

Explanation:

Formula

Heat = m * c * deltaH

Givens

m= 0.5 kg

c = 3400 J / (kg * oC)

Deltat = (100oC - 20oC)

deltat = 80oC

Solution

Heat = 0.5 kg * 3400 J/(kg* oC) * 80oC

Heat = 136000 Joules

Heat = 136 kg

Technically there is only 1 place of accuracy.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2