Physics, 26.10.2019 05:43 alejandra1201

The k-shell ionization energy of iron is 8500 ev, and it's l-shell ionization energy is 2125 ev. what is the wavelength of kalpha x-rays emmited by iron?

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Answer from: evanwall91

$1.95\cdot 10^{-10}m$

Explanation:

First of all, we need to calculate the energy of the x-ray photon emitted during the transition from K-shell to L-shell, and this energy is equal to the difference in energy between the two levels:

E=E_K-E_L=8500 eV-2125 eV=6375 eV

Converting into Joules,

$E=6375 eV \cdot (1.6\cdot 10^{-19} J/eV)=1.02\cdot 10^{-15} J$

Now we know that the energy of the photon is related to its wavelength by:

$E=\frac{hc}{\lambda}$

where

h is the Planck constant

c is the speed of light

$\lambda$ is the wavelength

Re-arranging the equation for $\lambda$ , we find

$\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{1.02\cdot 10^{-15} J}=1.95\cdot 10^{-10}m$

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Answer from: Quest

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explanation:

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The k-shell ionization energy of iron is 8500 ev, and it's l-shell ionization energy is 2125 ev. wha...

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