Light of wavelength 648.0 nm is incident on a narrow slit. the diffraction pattern is viewed on a screen 57.5 cm from the slit. the distance on the screen between the second order minimum and the central maximum is 1.05 cm . what is the width of the slit in micrometers (μm)?

Explanation:

The formula for the single-slit diffraction is

where

y is the distance of the n-minimum from the centre of the diffraction pattern

D is the distance of the screen from the slit

d is the width of the slit

is the wavelength of the light

In this problem,

, with n=2 (this is the distance of the 2nd-order minimum from the central maximum)

Solving the formula for d, we find:

1= 26.17

2= 1.17

3=30.86

4=5.86

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