At 20°c, a length of copper wire has a resistance of 10.0 ω what is its resistance when the wire is heated to 65°c? let α = 0.004 at 20°c. show all work and include units of measure.

= 11.8 Ω

Explanation:

Using the equation;

RT = Rr [1 + α (T -Tr)

Where;

RT = Resistance of conductor at temperature T

Rr = Resistance of conductor at reference temperature Tr

α = Temperature coefficient of resistance at reference temperature Tr

Therefore;

RT = 10 Ω [ 1 + 0.004( 65-20)]

    = 10 ( 1 + 0.004(45))

     = 11.8 Ω

nah.   i'm just sleepy.