Perhaps the most-common gravitational calculation is to determine the "weight" of an object of mass mo sitting on the surface of the earth (i. e., the size of the gravitational attraction between the earth and the object). according to newton's law of universal gravitation, the gravitational force on the object is fg=g(memor2e)=(gmer2e)mo, where me is the mass of the earth and re is the distance between the object and the center of the earth (i. e., re = radius of the earth = 6.38×103km). part f what is the value of the composite constant (gme/r^2e), to be multiplied by the mass of the object mo in the equation above? express your answer numerically in meters per second per second.

answer:

explanation:

the resolution of the eye is ultimately limited by the pupil diameter. what is the smallest diameter spot the eye can produce on the retina if the pupil diameter is 2.38 mm? assume light with a wavelength of λ = 550 nm. (note: the distance from the pupil to the retina is 25.4 mm. in addition, the space between the pupil and the retina is filled with a fluid whose index of refraction is n = 1.336.) hint: the size of the spot is twice the distance from the main axis to the first minimum.

double the distance = divide strength by 4

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement