For a satellite to be in a circular orbit 590 km above the surface of the earth, what orbital speed must it be given? express your answer with the appropriate units.

7.57 km/s

Explanation:

The gravitational force on the satellite provides the centripetal force that keeps the satellite in circular orbit, so we can write:

where

G is the gravitational constant

is the Earth's mass

m is the satellite's mass

r = R+h is the distance of the satellite from the Earth's centre, where:

is the Earth's radius,

is the altitude of the satellite above Earth

v is the orbital speed of the satellite

Solving the equation for v, we find

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c) up is the direction the magnetic force is acting on the charge.