Asoccer ball is kicked with a speed of 22m/s at an angle of 35.0º above the horizontal. if the ball lands at the same level from which it was kicked, how long was it in the air?

2.57 seconds

Explanation:

The motion of the ball on the two axis is;

x(t) = Vo Cos θt

y(t) = h + Vo sin θt - 1/2gt²

Where; h is the initial height from which the ball was thrown.

Vo is the initial speed of the ball, 22 m/s , θ is the angle, 35° and g is the gravitational acceleration, 9.81 m/s²

We want to find the time t at which y(t) = h

Therefore;

y(t) = h + Vo sin θt - 1/2gt²

Whose solutions are, t = 0, at the beginning of the motion, and

t = 2 Vo sinθ/g

  = (2 × 22 × sin 35°)/9.81

  = 2.57 seconds

answer: good job it's all correct !

explanation:

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it