Ahot metal bolt of mass 0.05 kg and specific heat capacity 889 joules per kg degree celsius is dropped into a calorimeter containing 0.15 kg water at 21 degrees celsius. the bolt and water resch a final temperature of 25 degrees celsius. what is the initial temperature of the bolt? the specific heat capacity of water is 4186 joules per kilogram degrees celsius.

80.87 °C

Change in Temp of metal = (C of water *mass of water* Change in temp of water)/(C of metal*mass of metal)

That is;

Change of temp. of metal

   = [(4186 J/kg*°C)×(0.15kg)×(25°C-21°C)/[(899 j/kg*C)×(0.050kg)

     = 55.87 °C

The change in temp of the metal is -55.87 °C  as the metal cools down

Therefore;

Change in temperature = Final Temperature-Initial Temperature Initial                                       Temperature = Final Temp.-Change in Temp

                      =25 °C- (-55.87 °C)

                       = 80.87 °C

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray

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