Atransformer has 1400 turns on the primary and 110 on the secondary.? if the primary is connected to a 120v outlet and draws 3.0x10^-2 amps, what are the voltage and current of the secondary? a) 1500 v, 2.4x10^-3 a b) 1500 v, 0.38 a c) 9.4 v, 2.4x10^-3 a d) 9.4 v, 0.38 a

D) 9.4 V, 0.38 A

1) Voltage in the secondary coil: 9.4 V

The transformer equation states that:

where

Vp = 120 V is the voltage in the primary coil

Np = 1400 is the number of turns in the primary coil

Vs = ? is the voltage in the secondary coil

Ns = 110 is the number of turns in the secondary coil

Solving the formula for Vs, we find

2) Current in the secondary coil: 0.38 A

A transformer is considered to be 100% efficient: it means that there is no loss of power, so the power in input is equal to the power in output

where

Vp = 120 V is the voltage in the primary coil

is the current in the primary coil

Vs = 9.4 V is the voltage in the secondary coil

is the current in the secondary coil

Solving the equation for ,

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a=d/t

a="triangle"v/t

explanation:

a = acceleration