An astronaut has landed on planet n-40 and conducts an experiment to determine the acceleration due to gravity on that planet. she uses a simple pendulum that is 0.640 m long and measures that 10 complete oscillations 26.0 s. what is the acceleration of gravity on planet n-40?

3.73 m/s^2

Explanation:

The period of a simple pendulum is given by

(1)

where

L is the length of the pendulum

g is the gravitational acceleration on the planet

The pendulum in the problem has length

L = 0.640 m

and makes 10 oscillations in 26.0 s; it means that its frequency is

And so its period is

So now we can solve equation (1) using L=0.640 m and T=2.6 s, so we can find the value of g on the planet:

specific latent heat of fusion, lf, of a substance is defined as the amount of heat required to change a unit mass of the substance from solid to liquid state, without any change in the temperature.

explanation:

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2