Suppose that the strength of the electric field about an isolated point charge has a certain value at a distance of 4 m. how will the electric field strength compare at a distance of 8 m from the point charge? 1. at twice the distance the field strength will be twice the original value. 2. at twice the distance the field strength will be 1 3 of the original value. 3. at twice the distance the field strength will be 1 2 of the original value. 4. at twice the distance the field strength will be 1 4 of the original value. 5. at twice the distance the field strength will be the same.

4. At twice the distance the field strength will be 1/4 of the original value

Explanation:

The magnitude of the electric field produced by an isolated poitn charge is

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge

In this problem, the distance from the charge is doubled from 4 m to 8 m:

Therefore, the new electric field will be

So, the field strength is 1/4 of the original value.

absorption lines are where light has been absorbed by the atom thus you see a dip in the spectrum whereas.

emission spectra have spikes in the spectra due to atoms releasing photons at those wavelengths.

explanation: