Physics, 05.12.2019 12:31 maribel234

Eight different values of resistance can be obtained by connecting together three resistors 6.50 ω, 7.60 ω, and 1.70 ω in all possible ways. what are the values in the following situations? all the resistors are connected in series. ω all the resistors are connected in parallel. ω the 6.50 ω and 7.60 ω resistors are connected in parallel, and the 1.70-ω resistor is connected in series with the parallel combination. ω the 6.50 ω and 1.70 ω resistors are connected in parallel, and the 7.60-ω resistor is connected in series with the parallel combination. ω the 7.60 ω and 1.70 ω resistors are connected in parallel, and the 6.50-ω resistor is connected in series with the parallel combination. ω the 6.50 ω and 7.60 ω resistors are connected in series, and the 1.70-ω resistor is connected in parallel with the series combination. ω the 6.50 ω and 1.70 ω resistors are connected in series, and the 7.60-ω resistor is connected in parallel with the series combination. ω the 7.60 ω and 1.70 ω resistors are connected in series, and the 6.50-ω resistor is connected in parallel with the series combination. ω additional materials

Answers: 3

Show answers

Answers

Answer from: Amyra2003

Before starting with the problem, let's remind that:

- Total resistance of a combination of resistors in series is:

R_T=R_1+R_2+....

- Total resistance of a combination of resistors in parallel is given by:

$\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}+...$

Now let's apply these equations to solve the different parts of the problem:

1. All the resistors in series: $15.8 \Omega$

In this case, the total resistance is

$R_T=6.50\Omega +7.60\Omega+1.70\Omega=15.8 \Omega$

2. All the resistors are connected in parallel: $1.14 \Omega$

In this case, the total resistance is

$\frac{1}{R_T}=\frac{1}{6.50 \Omega}+\frac{1}{7.60 \Omega}+\frac{1}{1.70 \Omega}=0.874\Omega^{-1}\\R_T=\frac{1}{0.874 \Omega^{-1}}=1.14 \Omega$

3. The 6.50 Ω and 7.60 Ω resistors are connected in parallel, and the 1.70-Ω resistor is connected in series with the parallel combination: $5.20 \Omega$

The total resistance of the two resistors connected in parallel is

$\frac{1}{R_T}=\frac{1}{6.50 \Omega}+\frac{1}{7.60\Omega}=0.285\Omega^{-1}\\R_T=\frac{1}{0.285 \Omega^{-1}}=3.50 \Omega$

And the combination of these with the other resistor of 1.70-Ω in series gives a total resistance of

$R_T=3.50 \Omega+1.70 \Omega=5.20 \Omega$

4. The 6.50 Ω and 1.70 Ω resistors are connected in parallel, and the 7.60-Ω resistor is connected in series with the parallel combination: $8.95 \Omega$

The total resistance of the two resistors connected in parallel is

$\frac{1}{R_T}=\frac{1}{6.50 \Omega}+\frac{1}{1.70\Omega}=0.742\Omega^{-1}\\R_T=\frac{1}{0.742 \Omega^{-1}}=1.35 \Omega$

And the combination of these with the other resistor of 7.60-Ω in series gives a total resistance of

$R_T=1.35 \Omega+7.60 \Omega=8.95 \Omega$

5. The 7.60 Ω and 1.70 Ω resistors are connected in parallel, and the 6.50-Ω resistor is connected in series with the parallel combination: $7.89\Omega$

The total resistance of the two resistors connected in parallel is

$\frac{1}{R_T}=\frac{1}{7.60 \Omega}+\frac{1}{1.70\Omega}=0.720\Omega^{-1}\\R_T=\frac{1}{0.720 \Omega^{-1}}=1.39 \Omega$

And the combination of these with the other resistor of 6.50-Ω in series gives a total resistance of

$R_T=1.39 \Omega+6.50 \Omega=7.89 \Omega$

6. The 6.50 Ω and 7.60 Ω resistors are connected in series, and the 1.70-Ω resistor is connected in parallel with the series combination: $1.52 \Omega$

In this case, the total resistance of the two resistors in series is

$R_T=6.50\Omega + 7.60\Omega=14.10 \Omega$

And the combination of these with the other resistor of 1.70-Ω in parallel gives a total resistance of

$\frac{1}{R_T}=\frac{1}{14.10 \Omega}+\frac{1}{1.70\Omega}=0.659\Omega^{-1}\\R_T=\frac{1}{0.720 \Omega^{-1}}=1.52 \Omega$

7. The 6.50 Ω and 1.70 Ω resistors are connected in series, and the 7.60-Ω resistor is connected in parallel with the series combination: $3.94 \Omega$

In this case, the total resistance of the two resistors in series is

$R_T=6.50\Omega + 1.70\Omega=8.20 \Omega$

And the combination of these with the other resistor of 7.60-Ω in parallel gives a total resistance of

$\frac{1}{R_T}=\frac{1}{8.20 \Omega}+\frac{1}{7.6\Omega}=0.254\Omega^{-1}\\R_T=\frac{1}{0.720 \Omega^{-1}}=3.94 \Omega$

8. The 7.60 Ω and 1.70 Ω resistors are connected in series, and the 6.50-Ω resistor is connected in parallel with the series combination: $3.83\Omega$

In this case, the total resistance of the two resistors in series is

$R_T=7.60\Omega + 1.70\Omega=9.30 \Omega$

And the combination of these with the other resistor of 6.50-Ω in parallel gives a total resistance of

$\frac{1}{R_T}=\frac{1}{9.30 \Omega}+\frac{1}{6.50\Omega}=0.261\Omega^{-1}\\R_T=\frac{1}{0.720 \Omega^{-1}}=3.83 \Omega$

Answer from: Quest

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.

Answer from: Quest

Caredbajshjn i belgajsbajbabasbbaba

Another question on Physics

Physics, 22.06.2019 04:20

Astone is thrown into a pond. what happens to the amplitude of the resulting waves as they get farther from the point where the stone hit the water? explain.

Answers: 3

Answer

Physics, 22.06.2019 05:00

Which statements describe the movement of ocean currents around the globe? check all that apply. strong winds force warm water to sink to the ocean floor. the coriolis effect causes warm and cold water to mix. cool dense water sinks to the ocean floor. warm water replaces cool surface water. wind blowing parallel to the shore causes upwelling of cool water.

Answers: 1

Answer

Physics, 22.06.2019 10:30

The freezing and boiling point of a substance changes as the air pressure around it changes. for example, at a lower air pressure (higher altitude) it is easier for water molecules to escape from liquid into the air. in a high altitude city such as denver, colorado compared to a sea-level city such as houston, texas, water

Answers: 2

Answer

Physics, 22.06.2019 17:20

In a system with only a single force acting upon a body, what is the relationship between the change in kinetic energy and the work done by the force? answers: work is equal to the change in kinetic energy.work depends on the square of the change in potential energy.work is equal to the negative of the change in kinetic energy.work is equal to the square of the change in kinetic energy

Answers: 2

Answer

You know the right answer?

Eight different values of resistance can be obtained by connecting together three resistors 6.50 ω,...

Questions

Physics, 28.07.2019 05:30

The attractive force that acts between all objects is the electromagnetic force gravitational force strong nuclear force weak nuclear force...