Aseries combination of two resistors, 7.25 ω and 4.03 ω, is connected to a 9.00 v battery.

a. calculate the equivalent resistance of the circuit and the current.

b. what is the potential difference across each resistor?

a.

The equivalent resistance of a series combination of two resistors is equal to the sum of the individual resistances:

In this circuit, we have

Therefore, the equivalent resistance is

b. 5.8 V, 3.2 V

First of all, we need to determine the current flowing through each resistor, which is given by Ohm's law:

where V = 9.00 V and . Substituting,

Now we can calculate the potential difference across each resistor by using Ohm's law again:

i think its

the answer is a 3.8cm

explanation: