"a car traveling on a flat (unbanked), circular track accelerates uniformly from rest with a tangential acceleration of 1.45 m/s2. the car makes it one quarter of the way around the circle before it skids off the track. from these data, determine the coefficient of static friction between the car and track"

0.148

Explanation:

For a car travelling on a flat curve, the centripetal force is provided by the frictional force between the tires and the road:

where

m is the car's mass

v is the tangential speed

r is the radius of the curve

is the coefficient of static friction

g is the gravitational acceleration

Dividing by m (the mass), we obtain an expression for the centripetal acceleration:

Therefore, by substituting a = 1.45 m/s^2 and g =9.8 m/s^2, we can solve the formula to find the coefficient of static friction:

answer: strength i guess

explanation:

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2