Alate traveler rushes to catch a plane, pulling a suitcase with a force directed 30.0° above the horizontal. if the horizontal component of the force on the suitcase is 60.6 n, what is the force exerted on the handle?
a.
53.0 n
c.
65.2 n
b.
70.0 n
d.
95.6 n

the normal force times the coefficient of kinetic friction  

The suitcase handle at 30 degrees means that the height of the end off of the ground is half as long as the strap since that ratio is the sine of that 30 degree angle, or 0.5. That gives us a right triangle with legs of (3)^1/2 [square root of three] and one, and a hypotenuse of 2. The hypotenuse of this triangle is 70, with the legs being 35 and 60.6 since (70)^2 = (60.6)^2 + (35)^2  

The car must add the power lost to friction, which is the car's weigh times the coefficient of friction while moving (kinetic).

Answer

B.) 70.0 N

Hope I helped!

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